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5x^2=265
We move all terms to the left:
5x^2-(265)=0
a = 5; b = 0; c = -265;
Δ = b2-4ac
Δ = 02-4·5·(-265)
Δ = 5300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5300}=\sqrt{100*53}=\sqrt{100}*\sqrt{53}=10\sqrt{53}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{53}}{2*5}=\frac{0-10\sqrt{53}}{10} =-\frac{10\sqrt{53}}{10} =-\sqrt{53} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{53}}{2*5}=\frac{0+10\sqrt{53}}{10} =\frac{10\sqrt{53}}{10} =\sqrt{53} $
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